Bash Loop Error

[Col8eral]

Try to run a simple loop script

#!/bin/sh
max=10
for (( i=2; i <= $max; ++i ))do
echo"$i"
done

but im getting "syntax error: bad for loop variable" when I run it. Wht am I doing wrong?
Thanks.

 

[Viktor Jaep]

Try to run a simple loop script

#!/bin/sh
max=10
for (( i=2; i <= $max; ++i ))do
echo"$i"
done

but im getting "syntax error: bad for loop variable" when I run it. Wht am I doing wrong?
Thanks.

Just a quick clarification. Our routers use POSIX, not Bash. (You can enable it if you so choose, but it gets more messy). POSIX shell has issues with advanced loops like this... you probably want to use something like this:

i=0
while [ $i -le 10 ]; do
    echo "$i"
    i=$(( i + 1 ))
done

 

[Col8eral]

Thank you. I tried that and got this error:
loop: line 7: syntax error: unexpected end of file (expecting "do")

 

[Viktor Jaep]

Thank you. I tried that and got this error:
loop: line 7: syntax error: unexpected end of file (expecting "do")

Make sure set the environment at the top:

#!/bin/sh

i=0
while [ $i -le 10 ]; do
    echo "$i"
    i=$(( i + 1 ))
done

exit 0

This works for me: